Escaping wildcard character * in bash script

[jclim]

Hello Linux ppl!

I need some help with processing wildcard character * in my bash script. My script writes:

OUTPUT=$(du -sh backup* 2>&1)

Whenever this line is executed, backup* is interpreted explicitly as backup* instead of all files starting with the word backup.

Thanks in advance!

[Cabhan]

That is interesting, as mine does not:

alex@danu:~$ OUTPUT=$(du -sh down* 2>&1); echo $OUTPUT
404M downloads

Perhaps you forgot that you are storing the output of that command in $OUTPUT, and forgot to echo it?

[jclim]

Thanks for your response.

It works differently if written in a script file.

The solution goes like this: OUTPUT=$( du -sh backup* 2>&1 )
I have added spaces after the opening parenthesis and before the closing parenthesis.

I hope this help others with the same problem.