ispell question

[Utnubu]

hello friends,,
my problem is about ispell

when i enter three argument to a script which is coded.
if the word is spelled correctly, it will show 'you entered true word'
if the word is misspelled, it will show 'you entered wrong word"
if you cannot enter an argument, it will show you 'no argument and exit'

if [[ -z $1 ]]; then echo 'No argument is given, the script exits'; else echo ... ?

how can i do it?
i want to control it with 'echo word | ispell -l'

thanks for your answers.

[daedae]

You could do something like the below shell script. Store the output of "ispell -l" in a variable, then test to see if it's not empty ( -n ).

#!/bin/bash

if [ $# -eq 0 ]
then
    echo "No arguments given. Exiting."
    exit 1
fi

ispell_out=$(echo $1 | ispell -l) 

if [ -n "$ispell_out" ]
then
    echo "Misspelled word: $1"
else 
    echo "Correctly spelled word: $1"
fi