gawk and shell variables

[jody]

Hi

I need to use a shell variable inside a gawk expression,
but i don't manage to do it the way i want to.

To be more specific:
Assume data.txt is

200 312
122 -53
9 123
44 0

i now want to create a script file with the lines

yprocess 312 [some-complex-parameter-list] >> mod.txt
yprocess -53 [some-complex-parameter-list] >> mod.txt
yprocess 123 [some-complex-parameter-list] >> mod.txt
yprocess 0 [some-complex-parameter-list] >> mod.txt

so what i tried is:

a=$1
b=calculate_complex_parameter_list  $a

cat $a | gawk '{ print "yprocess " $2 " $b >> mod.txt" }'

but this gives me

yprocess 312 $b >> mod.txt
yprocess -53 $b >> mod.txt
yprocess 123 $b>> mod.txt
yprocess 0 $b >> mod.txt

when i move the $b outside of the double quotes:

a=$1
b=calculate_complex_parameter_list $a

cat $a | gawk '{ print "yprocess " $2 " " $b " >> mod.txt"  }'

i get

yprocess 312 200 312 >> mod.txt
yprocess -53 122 -53 >> mod.txt
yprocess 123 9 123 >> mod.txt
yprocess 0 44 0 >> mod.txt

i.e. $b is replaced by the current line emitted by cat

In reality, my data file has several hundred lines,
and the complex parameter list consists of several hunderd numbers.

Is there any way to achieve this goal (with or without gawk=?

Thank You
jody

[gerard4143]

try something like below

#! /bin/sh

echo -n "enter something->"
read mymsg

echo $mymsg | awk '{printf("%s\n", $0)}'

Or...

#! /bin/sh

echo -n "enter something->"
read mymsg

myval="123456789"

myeval="echo $mymsg | awk '{printf(\"%s $myval\\n\", \$0);}'"

eval $myeval