pattern matching - plz guide

[apurv30]

#cat test.sh
if test $1 = '\[1*\]'
then
echo "Yes is a Matching Pattern"
else
echo "Not a Matching Patern"
fi

but this does not match for 1 , 11 or 111
it matches foronly 1*

also tried using the following
if [ $1 = [1*] ] - - > did not match for 11
if [ $1 -eq [1*] ] - - > it complains test.sh: line 2: [: [1*]: integer expression expected

Can any body tell me y the pattern matching is not hapening?

[jeremy1701]

How about

if test $1 = "1*"

Double quotes instead of single quotes? I think you can safely remove the [] as well.

Jeremy

[sarumont]

How about

if test $1 = "1*"

Double quotes instead of single quotes? I think you can safely remove the [] as well.

Jeremy

No...you need the [...]. That is the bash construct for conditional testing.

Try this:

if [ $1 = [1]* ]; then
     echo "It matches!";
else
    echo "No match!";
fi

Are you trying to match any combination of 1's? This will only match a 1 with anything after it at all. I'm not sure how you would go about matching a pattern of 1's in bash, but I'll research it.

Edit: That doesn't work, either. I don't know how to go about doing this....