convert string to int array

[bond_006]

I've searched around and can't find out how to convert a string ( like "12345" ) into an int array ( x[ 5 ] = { 1, 2, 3, 4, 5 } ; ).

[GNU-Fan]

atoi [C++ Reference]

[Rubberman]

atoi [C++ Reference]

While atoi() or strtol() will convert a string into numbers, I think the question was how to convert each letter into an entry in an array of ints.

const char* pStr = "12345";
size_t len = strlen(pStr);
int iStr[len];

for (size_t i = 0; i < len; i++)
{
    iStr[i] = pStr[1] - '0';
}

If this is a class problem, consider this your one "freebee".

[Schmidt]

While atoi() or strtol() will convert a string into numbers, I think the question was how to convert each letter into an entry in an array of ints.

const char* pStr = "12345";
size_t len = strlen(pStr);
int iStr[len];

for (size_t i = 0; i < len; i++)
{
    iStr[i] = pStr[1] - '0';
}

If this is a class problem, consider this your one "freebee".

it seems that you should use malloc() after strlen(), not static declaration

[Rubberman]

Actually, the only problem with the code I showed was the loop declaration of the variable 'i' which won't compile with C89, but will with C++. If you move the delcaration out of the loop, then it will compile and run just fine with either a C or C++ compiler.