Need help with using Grep/Variables in bash script

[dragin33]

Hi linux users! I'm trying to write a bash script and I'm having trouble with it. I have a list of DNS entires from a file called zoneExport.txt. Than I want to parse a log file to see if that DNS entry has been queried for. So I'm running a grep command and trying to save it into a variable. What I'm looking for is a variable ($varGrepQ) that has the number of matches for the grep query. I will then run this through an if statement and do some things from there..

But my problem right now is with this grep query. It keeps outputting '0' even when I know there are records in that file and when I run the same query on the command line I get the actual count. My thought is that the $record variable is not passing right. Any thoughts?

#!/bin/bash
varLines="$( cat ~/Desktop/DNSLogs/zoneExport.txt )"
for record in $varLines; do
echo $record
#varGrepQ=`grep -c -i "$record" ~/Desktop/DNSLogs/test.log`
varGrepQ=$(grep -c -i "$record" ~/Desktop/DNSLogs/test.log)
echo $varGrepQ;
done

[nmset]

Could you post samples of both files ? I have not found errors with test data. zoneExport.txt should have one single word per line for the for loop to be valid in this setting.

[dragin33]

I had to rename test.log to test.log.txt to get it to upload.

[dragin33]

Hi. I think I found my problem.. The file I was pulling the source zone from was windows formatted and so I was pulling these odd newline ^M characters in with my variable and obviously that wasn't present in the other file.

Thanks!

[nmset]

I found it a very tough one and I had no clues at what was wrong. Good to read a logical reason.