Tell me this stuff with Pointers

[maheshgupta024]

hi, please can anyone solve my doubt.
#include <stdio.h>

#include <stdio.h>
main()
{
char names[2][10] =
{
"ABCDEF",
"GHIJKL"
};
char **ptr;
ptr = names;
printf("%s\n", ptr+1);
}

For this program, I expected that output should be GHIJKL, But the output is EF.

and if I change the ptr+1 to ptr[1], then there is a seqfault, what does this mean.

Thanks in advance.
Mahesh Gupta.B

[Lakshmipathi]

If i'm not wrong - i think it should char* .

#include <stdio.h>
main()
{
char names[2][10] =
{
"ABCDEF",
"GHIJKL"
};
char *ptr;
ptr = names;
printf("%s\n",ptr);
printf("%s\n", ptr + 10);
}

[Rubberman]

This really looks like school work. Remember that it is not allowed to ask for help solving classwork in the forums!