copy all files with the same filenames as those in another folder

[jiapei100]

Hi, all:

I've got two folders, folder A contains some image files (say, 100 files) in .jpg format;
folder B contains all description files (say, 500 files) in .txt format.

All image files in folder A are able to find their corresponding description files in folder B.
That is to say, regardless of file extension, 100 .txt files in folder B share the same name as those 100 .jpg files, for example 00011020.jpg in folder A is able to find its corresponding 00011020.txt in folder B.

Now, my question is:
How to just copy out the 100 description .txt files that share the same name as those 100 image files, out from folder B into folder C( or create folder C first, and then carry out the copy) ?

Looking forward to your help.

Best Regards
JIA Pei

[Rubberman]

School work?

[jiapei100]

Haha...
not at all.
My task.
Sorry, I'm not a specialist in script.

[Irithori]

Hmm,
in dubio pro reo

This oneliner is hack-ish as it lives on certain assumptions and has no errorchecking.
Also, the multiple cp can be optimized.
So dont use that as a cronjob and just for one time shots

Assumptions
- directories A, B and C exist
- and are on the same level
- the script is called from the directory containing A,B and C

for FILE in `find A/ -type f -iname "*.jpg" |sed s#A/##| sed s/\.jpg$// | sort |uniq`; do cp B/$FILE.txt C/;done