Regular Expression in String Comparison

[coolboarderguy]

Hi All,

how do I get this regular expression to work in an if/else statement? This is just a little script for learning BASH. Please don't be too harsh. Thanks.

#!/bin/sh
#
#
#This script will test if a certain number of files with 1-4 in their filename exist and print their filename. An error message will be printed if not.
#
for i in `ls file[1-9]`
do
if [[ "$i" == *1-4 ]] ; then
        echo "This file, $i, ends in a number between 1-4"
else
        echo "Error, this file, $i, does not end with a number between 1-4"
fi
done

I get this error.

./file_test.sh: 13: [[: not found

[Kloschüssel]

#!/bin.bash
FILES="$@"
regex="[1-4]+"
for f in $FILES
do
if [[ $f =~ $regex ]]; then
 echo "$f : yes";
else
 echo "$f : no";
fi
done

and use it like this:

has_1_to_4_in_name mydir/*

Mostly got all information from google, which lead me here.

EDIT: I like the signature of the above post; well .. learn to use google. some may offer a workshop?

[drl]

Hi.

I would use bash, ksh, or zsh in place of sh ... cheers, drl