unalias not working?

[zmunkz]

Hey guys... I'm a bit stuck, and hoping someone can help me out.

I wrote some bash code to prevent redundantly including files, like php's "include_once". I've simplified it here so don't worry that it appears not to do anything:

alias .='Include'
alias source='Include'
export __INC__functions=1

function Include {
    local name="__INC__"`basename ${1%\.*}`
    eval "export $name=1"

    unalias source
    source $1
    alias source='Include'
}

For some reason this is not working. Although I "unalias source" inside the "Include" function, the very next line is still calling "Include". Here is what I see with set -v -x:

...
++ eval 'export __INC__mysql_functions=1'
export __INC__mysql_functions=1
+++ export __INC__mysql_functions=1
+++ __INC__mysql_functions=1
++ unalias source
++ Include /home/fonix/client_progs/cs/utils/mysql_functions.sh
...

the unalias appears to work, but the next call to source is treated as the original alias. Does anyone know why it would do this? Are aliases replaced within a function at the start of the function, or perhaps when the function is defined? Is there a way to get this to work?

Thanks in advance!

[zmunkz]

I do see this in the MAN page which does explain the behavior:

"Aliases are expanded when a function definition is read, not when the function is executed, because a function definition is itself a compound command."

So I guess I'll just ask the last question I had. Is there a way around this?