ls exclude directories

[r31griffo]

G'day everyone,

I'm having trouble figuring out how to list the contents of a directory and exclude any subdirectories.

Currently I have:

 ls --width=1 ${FILEDIR}/ | grep -v '^Thumbs.db' $1 > ${FILES}

The output is the correct format, any help someone can give me with this would be awesome.

Cheers,

Griffo

[r31griffo]

I'm sorry, I meant to take the variables out when I posted to make it a little easier to read. When the script runs, it uses the values below.

 ls --width=1 /mnt/ | grep -v '^Thumbs.db' $1 > files.txt

[blinky]

Not sure ls can do that (I've never mmanaged to make it do it), but this should work

find /mnt -name "*"  ! -type d -maxdepth 1  -printf "%f\n"

[r31griffo]

Thanks for the reply, it works and it is the correct format to use in my script. But...when I pipe or direct the output to another program or file I receive an error on my display even though the file I'm creating is fine. Using the command you provided, I've added grep to strip Thumbs.db from the list.

find /mnt -name "*"  ! -type d -maxdepth 1  -printf "%f\n" | grep -v '^Thumbs.db' $1 > files.txt

The error I get is:

find: warning: you have specified the -maxdepth option after a non-option argument -name , but options are not positional (maxdepth affects tests specified before it as well as those specified after it). Please specify options before other arguments.

I'm not sure if the version of find is an issue here, I'm using Debian Lenny (but will soon be upgrading to Squeeze).

It would be great if I could get rid of this error message, any ideas you have would be greatly appreciated.

Cheers,

Griffo

[blinky]

try

find  /mnt -maxdepth  1 -name "*"  ! -type d  -printf "%f\n"

I get the same error/warning message if the find returns no results, the above seems to fix/(get rid of) it.

[r31griffo]

Perfect, that's exactly what I was after. I piped it to grep and sent the output to a file and no error message.

Thanks mate,

Griffo