Problem Generating Log

[hirav]

Hi all,

I am working on a bash script in which I have to check for some command & want the output of that command to be saved in a file.

suppose if I fire a command wget w3.google.com (I am not allowed to post URL in forum) then i ll get some log printed on console .. I want to save that log in my log file.

Please help me solve this issue

Thanks in advance.

[Irithori]

Just direct standard out to a file.
wget wwww.google.de > /tmp/logfile
or the standard error
wget wwww.google.de 2> /tmp/logfile
or both
wget wwww.google.de > /tmp/logfile 2>&1

[Irithori]

You could also utilize the existing syslog.
Have a look at

man logger

[lenfree84]

try use the tee command..

[pdk]

put set -x in the script and then direct the output to a file
myprog > log
Peter

[hirav]

thnx for you support..

I have tried out standard output to my file & but the problem is something else

my command (I have written wget here instead ) shows full loading process, i mean 0% to 100% task completion & at the end it shows done successfully or failed..

I just want that status to be appended in the file ..

Can you please help me bit more as I am totally new to shell scripts.

Thanks again

[pdk]

When a job completes in a shell there is a variable that stores a 1 or 0 depending on pass or failure. I think it is the '?'
if [ "?" == 1 ]
then
echo "task failed"
fi
something like the above. I write so few scripts these days and forget the exact format. Hope this helps.
You will have to read man bash to find the correct variable.
Peter

[djeyewater]

Expanding on pdk said, $? is the variable that holds the exit code of the last command. 0 means okay, anything else means failed.

if [ $? -eq 0 ]
then
echo "task completed" > log.log
else
echo "task failed" > log.log
fi