Bash command to remove all files within a specific folder

[Shayno90]

I want to delete all files within a specific folder without actually deleting the folder, what is a good bash command for this?. I found this one but encountered some errors even though I am executing it within the specific folder:

useratdebian:/home/user/folder# find . -type f -exec rm -rf {} \;
[1] 5052
useratdebian:/home/user/folder# find: missing argument to `-exec'

[1]+ Exit 1 find . -type f -exec rm -rf

The command as it appears is:

find . -type f -exec rm -rf {} \;

Any ideas of how to delete only the files contained within the folder called "folder" for example?

[Irithori]

You copy&paste is wrong.

The command should be something like

find <FOLDER> -type f

Replace <FOLDER> with the actual path
If that returns *only* the files you want to delete:

find <FOLDER> -type f -delete

fyi:
You can also work with -exec, the syntax would be

find <FOLDER> -type f -exec rm -f {} \;

[Shayno90]

Thanks/Danke Irithori!

Your 'find' command worked great!

I have another question:

I have about 36 other folders where I have to basically enter the folder pathname everytime, can the command be modified to delete the files contained within these folders, the folders are in this format:

A-ABC-20101020-0001 (numbers are in format DDMMYY-NN)
A-ABC-20100408-0002
A-ABC-20100306-0003
etc.....................................

So the command as it is, is:

find A-ABC-DDMMYY-NN/folder/subfolder -type f -delete

Can the command above be adjusted to delete files for each of the 36 folders in just one command without doing it for each separate folder?

[Irithori]

Use globbing:

find /<PATH_TO_DATADIR>/A-ABC-* -type f

[Shayno90]

Danke schoen Irithori.

The command works great, very effective for a simple command.

Now I will add a simple crontab job to execute it!