Displaying process id in my shell script but there is no such process

[vishnukumar]

Hi,

I have a shell script to identify whether the process is running or not. If the process is not running, then I execute another script file to run my application. Below is my script and saved this script as monitorprocess.sh

#!/bin/bash

result=$(ps -ef | grep -v grep | grep "applicationname.sh" | awk '{print $2}')
echo $result

if [ "$result" == "" ];
then
echo "process is not running"
sh applicationname.sh
fi

When I execute the script file as "sh monitorprocess.sh". I got printed with process id, something like 4726 4727. But, if I execute this ps -ef | grep -v grep | grep "applicationname.sh" | awk '{print $2}' in the shell. I got no output.

Actually, executing shell script should not print the process id, because the actual process is not running. Please, help me to fix it.

Thanks

[barriehie]

I would do it like this:

#!/bin/bash
#
appname="whatever.sh"
result=$(pidof $appname)
if [ $result ]
then
    echo "Process $appname running with PID $result"
else
    echo "Launching application $appname"
    sh $appname
fi

exit 0

[Rubberman]

If the process may be a shell script, you need to add the '-x' option to pidof. That will get the pid of processes and/or scripts.

[vishnukumar]

Hi,

I have fixed the issue with the script. The fix is, I have added the correct path to the shell script within another shell script. Below is my script

#!/bin/bash

result=$(ps -ef | grep -v grep | grep "reportgen.sh" | awk '{print $2}')

if [ "$result" == "" ];
then
sh /var/www/Reportgen/reportgen.sh $1 $2 $3 $4 $5 $6 $7
fi

[vishnukumar]

Barriehie, Rubberman,

I have tried with "pidof $appname" or "pidof -x $appname", however when the process is running, this script doesn't print any result. I also pasted this "pidof applicationname.sh" in the terminal and there is no output. I don't know how to use pidof?

QUOTE=Rubberman;814525]If the process may be a shell script, you need to add the '-x' option to pidof. That will get the pid of processes and/or scripts.[/QUOTE]