Number game Bash script

[xkaijinx]

Hey everyone,

I am trying to figure out the below script. I have to create a number guessing game which creates a random number (did that) and then it will tell you if the number is to low or to high or correct. Also to create a counter on how many attempts it took for you to reach that guess. I am halfway there, I keep getting an error that it just keeps saying "The number is smaller than your guess" no matter what I type in. Not sure how to make a counter in this script. Any help most appreciated!!!

#!/bin/bash
clear
RANGE=60
num=$RANDOM
let "num %= $RANGE"
counter=0
guess=-1
while [ " $guess" != "$num" ]
do
echo -n "I am thinking of a number between 1 and 60. Enter your guess:"
read guess
if [ "$guess" = "" ]
then
echo "Please enter a number."
elif
[ "$guess" = "$num" ]
then
echo "$guess is the correct answer!"
elif
[ "$guess" -gt "$num" ]
then
echo "The secret number is greater than your guess. Try again."
else
echo "The secret number is smaller than your guess. Try again."
fi
done
~

[alf55]

This looks like homework, we do not do assignments for people.

[Piyu_86]

in your code messages are wrong reverse them .

echo "The secret number is greater than your guess. Try again."
else
echo "The secret number is smaller than your guess. Try again."

for e.g ig random no. generated is 40 . and you guess is 39 it will print
The secret number is greater than your guess. Try again which is reverse .
just echo the numbers in your script and debug it .

and regarding counter u can implement that using for loop .

[cfajohnson]

Please put code inside code tags:

clear
RANGE=60
num=$RANDOM
let "num %= $RANGE"

num=$(( $RANDOM % $RANGE + 1 ))

counter=0
guess=-1
while [ " $guess" != "$num" ]

There should be no space after the quotes:

while [ "$guess" != "$num" ]

Then fix the logic as pointed out by the previous poster.