Day or night script?

[Grasroot]

First of all i just want to say that I'm quite new to bash scripting.

So, I'm trying to make a script to tell if it is day or night. The purpose of the script is to execute an action if it is day and a different one if it is night when the script is executed.

So far i have this:

#!/bin/bash
typeset -i TIME
typeset -i DAY
typeset -i NIGHT
TIME=$(date +"%H")
DAY='10'
NIGHT='20'
if [ ${TIME} -gt ${DAY} ]; then
echo "It's day!"
else
exit
fi
if [ ${TIME} -gt ${NIGHT} ]; then
echo "It's night!"
else
exit
fi

The problem here is that, when the clock is 21 (yes, I use a 24 hour clock), the script tells me it's both day and night. So how can i fix this to display only one of the options?

The echoes are only there for testing purposes.

[froop]

Assuming that you want it to return "Day" between 10:00 and 20:59, and return "Night" between 21:00 and 09:59, you might want to try this:

#!/bin/bash
TIME=$(date +"%H")
DAY='10'
NIGHT='20'
if [ ${TIME} -ge ${DAY} -a ${TIME} -le ${NIGHT} ]; then
   echo "It's day!"
else
   echo "It's night!"
fi