modifiers in bash

[jake_harv88]

I can't for the life of me figure out modifiers in bash. If someone could help me out that would be swell. Basically I'm trying to do a few things, none of which are working. Basically I have a filename that I'm saving to a variable. Then I want to just get the ending (everything but the suffix) of that file. In a separate command it would also be useful to change the suffix. So I have something like:

test="filename.com"
out="$test:r.o"
end="$test:e"
echo $out
echo $end

I usually get something like:

filename.com:r.o
filename.com:e

as the output. This works perfectly in zsh but I just can't seem to get it to work in bash. There should be a way to do this right? I've been able to get the ending with this:

echo "$test" | awk -F . '{print $NF}'

but it would be much easier to do with modifiers and I feel like it should be possible. Anyone have any suggestions?

[lomcevak]

If I understand you correctly try this:

echo ${out#*.}
echo ${end#*.}

man bash for details. It's in the Parameter Expansion section.

       ${parameter#word}
       ${parameter##word}
              The word is expanded to produce a pattern just  as  in  pathname
              expansion.  If the pattern matches the beginning of the value of
              parameter, then the result of  the  expansion  is  the  expanded
              value of parameter with the shortest matching pattern (the ‘‘#’’
              case) or the longest matching pattern (the ‘‘##’’ case) deleted.
              If parameter is @ or *, the pattern removal operation is applied
              to each positional parameter in turn, and the expansion  is  the
              resultant  list.   If parameter is an array variable subscripted
              with @ or *, the pattern removal operation is  applied  to  each
              member  of the array in turn, and the expansion is the resultant
              list.