Decimals issue using bash script

[yohisita]

Hi all,

I have the same problem. I'm doing a script to validate the Operating System RHEL. If the release is less than version 6 send me and message

function release {
rel=`cat /etc/redhat-release | grep "release" | awk '{print $7}'`
if [ $rel -lt 6 ] ; then
echo "less than 6"
else
echo "more than 6"

}


I know "-lt" is for interger numbers, i don't know how to do the condition with floating numbers... because the release is 5.5 & send me the error "syntax error: invalid arithmetic operator (error token is ".5")"

Someone can helpme with that issue, please ??

Thanks

[atreyu]

There's about a million ways to do this...here's one: Strip off the dot and everything after it w/sed:

rel=`cat /etc/redhat-release | grep "release" | awk '{print $7}'|sed -e 's|\..*$||'`