Using a incrementing variable in a for loop

[rootwanna]

Any one know a way to do this?

var1=true
var2=false
var3=true

for a in \$var{1..3};do
if [[ "$a" == "false" ]]; then
echo "Yay"
fi
done


where $a = would equal/equate to tha values of vars 1 - 3

[atreyu]

Is this what you mean?

var1=true
var2=false
var3=true

for a in $var1 $var2 $var3; do
  if [[ "$a" == "false" ]]; then
    echo "Yay"
  fi
done

[theMickey]

I think this is not exactly what he wants to do.

He has for example three variables which have the same basename but with a different number at the end (var1, var2, var3). Now he wants to access each variable by using something like this: $var$counter. And I think this can't be done.

[LSalab]

If that's the case, then perhaps he should consider arrays

var[1]=true
var[2]=false
var[3]=true

Then he can access the values like this:

${var[$COUNTER]}

[atreyu]

ah, if that's the case, how about:

#!/bin/bash
var1=true
var2=false
var3=true

for i in `seq 1 3`; do
  eval a=$(echo \$var$i)
  echo var $i is $a
  if [[ "$a" == "false" ]]; then
    echo "Yay"
  fi
done

[theMickey]

atreyu: Seems to work for me. But I am with LSalab, arrays are the better solution for this I think...

[atreyu]

yeah, definitely arrays are better, if the variable subnames are numbers. this solution is really more useful if the subnames are letters (or for some crazy reason you can't use arrays).