Bash - Variable with spaces and quotes passed to function - help!

[ak888]

I have a generic script that builds up the parameters to call rsync. I am trying to add an optional set of parameters and pass this into a function that generates and executes the rsync command. The extra parameters I want to pass is --rsh="ssh -p 2000".

So in my caller I have something along the lines of
EXTRAPARAM="--rsh=\'ssh -p 2000'"

Then I call the function
testFunc $PARAM

Running this shows (below) and seems to drop the arguments when it see the space.
++ ARG='-n --rsh=\'\''ssh'

If I call testFunc "$PARAM" to keep the whole variable contents I get
++ ARG='-n --rsh=\'\''ssh -p 2020\'\'''


As a test (not the real scripts) I wrote up the following to try various scenarios. Any one point me to the solution (if any?!)

set -x

testFunc() {

local ARG1=$1
ARG="-n"
ARG="$ARG $ARG1"

rsync $ARG
}
PARAM="--rsh=\'ssh -p 2000\'"

testFunc $PARAM
testFunc "$PARAM"

[atreyu]

How about a combination of escaping the double-quotes, and evaling it?, e.g.:

#!/bin/bash

testFunc() {
  opts="--rsh=\"ssh -p 22\""
}

testFunc

eval rsync $opts -av foo.txt remote_host:/tmp/

[ak888]

Think that works actually!