Command that displays owner of a file?

[blev]

I'm writing a script that searches user's files for IP addresses, and I'm trying to find a way to display the owner of the file.

[jayd512]

Hello and Welcome!

What about just using ls?
Using either the -l or -o options will display the owner.

[blev]

I was kind of hoping for a way to display

 Owner of File: "owner"

Without all of the other stuff that ls -l displays. Also, if I'm looking at a particular file with IP addresses, will ls still work, or will it just display everything in that particular directory?

[Irithori]

Something like this?

cd <DIRECTORY_WITH_THE_FILES>
egrep -Hr '([[:digit:]]{1,3}\.){3}[[:digit:]]{1,3}' * | cut -d ":" -f1 | sort | uniq | xargs -L 10 stat -c "%U %n"

Note: %U needs a valid name in /etc/passwd. In doubt, use %u

Note2: Yes, I know that the regex is not exact. Sue me

[blev]

thanks for that. It looks a lot like the cut that I was working on, but just couldn't get right.

[blev]

here's the part of the script I need help on

hammer=/home
dirs=$(ls $crank)
oof=`echo ls -o | cut -c 14-`
for user in "$crank"/*; do
         echo Username: "$oof"
         echo -e "\nPath: $user"