Echo Bash Variable to create PHP file.

[tamer1009]

Hey,

I got stuck coding a small bash script which creates a php file.

This is what I have so far but it seems not to be working:

#!/bin/bash
userid=</dev/urandom tr -dc A-Za-z0-9 | head -c 16
passid=</dev/urandom tr -dc A-Za-z0-9 | head -c 24
echo '<?php
$tempuid = "$userid";
$temppid = "$userid";
//php actions below.
?>' > userpass.php

When I edit userpass.php I see:

 <?php
$tempuid = "";
$temppid = "";
//php actions below.
?>  

Instead of the value of the variables.

Thanks

[atreyu]

Your first two commands are not putting the values into the variables, you need to use $() or `` to capture the command output.

When you echo the php code you need to use double-quotes in order to allow the variable expansion to happen. You'll also need to escape the PHP variable names, too.

e.g.:

#!/bin/bash
#userid=</dev/urandom tr -dc A-Za-z0-9 | head -c 16
userid=$(</dev/urandom tr -dc A-Za-z0-9 | head -c 16)
#passid=</dev/urandom tr -dc A-Za-z0-9 | head -c 24
passid=$(</dev/urandom tr -dc A-Za-z0-9 | head -c 24)
echo "userid: $userid"
echo "passid: $passid"
echo  "<?php
\$tempuid = \"$userid\";
\$temppid = \"$userid\";
//php actions below.
?>" > userpass.php

[tamer1009]

Thanks, finally after hours of trying and failing.

[atreyu]

np, been there done that. glad it got sorted.