Grep last pattern output of 2 (or more) input files

[Meternagel]

Hi
I'm referring to the following thread:
Grep last pattern output

My question is:
Which code has to be used, if we wanted to show the last pattern of each two (or more) input files?

Example:

File 1:
linux 56
slackware 32
debian 34
linux 2
redhat 9

File 2:
linux 11
slackware xx
debian 2
linux 3
redhat 7

The output should be:

linux 2
linux 3



Thanks for your help.

[Roxoff]

If you can't do your homework you should be discussing this with your tutor or teacher rather than asking us to do it for you.

Take a look at the man page for grep, it tells you all you need to know.

[Meternagel]

Its not part of a exercise, but thanks anyway. I don't know if you understand my problem. The referred problem was simpler and even that was solved by using additional programs to grep. Thats why I was not expecting much from going through the grep manual.

[Mudgen]

I don't think it's possible to understand your problem from your description. For the input/output specified
grep -h "linux [2,3]" *
would do it. But those are not the last patterns in the files, so your explanation of your homework problem doesn't make sense.

[Meternagel]

Thanks. I think you got my problem. But now lets I assume, the file would be much larger and it we would not know the LAST LINE in the file, containing "linux", so we dont know, that these lines containing 2 and 3. I am looking for a code, which gives from both files the last of all lines, containing "linux", independently from the other contents of the line.
And I must insist, that this is not a homework problem. I just try to learn sth which is useful for my studies but NOT ASKED BY ANY PROFESSOR!!!

[atreyu]

To grab the last file that matches, I'd pipe the output of grep to tail. If you want the number of the line in question, check out the '-n' flag.

[Meternagel]

Well thanks. The problem is, if I use
tail --lines=1
it replies
file2:linux 3
if I use
tail --lines=2
it replies
file2:linux 11
file2:linux 3

But I am looking for
file1:linux 2
file2:linux3

[atreyu]

i was assuming you were iterating over each file, my bad. do something like:

#!/bin/bash
# pass files as arguments to script
files=$@
# loop thru files
for file in $files; do
  grep -H linux $file|tail -n1
done

[Meternagel]

It works!!! Thats what I was looking forè

Thanks for your help.




?Do I have to do sth to close the thread, or show that my problem is solved? Did not find a directive.