[SOLVED] submenus in bash

[eamesj]

Hi all,

Trying to build a series of options in a bash script and im fine with 1 menu but i want to put a sub menu in one of the options...

#!/bin/bash
menu ()
{
clear
echo "-------------------------------"
echo " M A I N - M E N U"
echo " 1) option "
echo " 2) option "
echo " 3) option "
echo " 4) option "
echo "-------------------------------"
while
do
read action
case $action in
"1")
do something
;;
"2")
do something else
;;
"3")
submenu ()
{
clear
echo "-------------------------------"
echo "SUB -MENU"
echo "a) option"
echo "b) option"
echo "-------------------------------"
while :
do
read subaction
case $subaction in
"a")
do something ;;
"b")
do something else ;;
esac
done
}
submenu;
;;
"4")
echo "Bye!"
exit 0
;;
*)
echo "Error: Invalid option..."
read -p "Press [Enter] key to continue..." readEnterKey
;;
esac
done
}
menu;


but bash is complaining that there's a syntax error, can someone tell me how can i create in submenus in bash ?

thanks,

[eamesj]

Solved it

Hadnt added a ;; what i wrote is actually correct. Can see why its called bash...

solution:

3)
submenu ()
{
clear
echo "-------------------------------"
echo "SUB -MENU"
echo "a) option"
echo "b) option"
echo "-------------------------------"
while :
do
read subaction
case $subaction in
"a")
do something ;;
"b")
do something else ;;
esac
done
}
submenu;
;;
4)

[watael]

hi,

bash is complaining that there's a syntax error

«there's a tree in a forrest.» let me guess, it's made of wood! XD

what's the error message? exactly.

functions don't have to be nested because they are called inside another.

don't you have something to test in the first `while'?