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SED help with ^ first character in line.
6 00:01:28,172 --> 00:01:30,506 l vant to kiss your tush.
sed 's/ l / I /g' $i.b > $i.a
Thanks hazel, It looks like I would want to use something like
"\<l\>" "\<I\>" but how would I use that in a sed command? Or should I use a tr command?
If it doesn't work, there are other ways. I would use " l|^l" to specify that l must occur either after a space or at the beginning of a line.