bash, command line arguments

[Garrett85]

The variable OUTPUT remains contniues to be tied to ${6} even when there are 8 command line arguments given. The if statements sould reset OUTPUT to ${7} and FREQUENCY to ${6} but it will not. I need this script to configure dummy config file for radio bridges and access points. It works fine with the bridges but when I run it for the APs and I need the extra FREQUENCY variable it doesn't work, OUTPUT continues to be ${6}. Any ideas?

#/bin/bash
#
# example: ./configure input-file, SSID, IP, device-name, gateway, frequency, output-file
#
FILE=${1}
SSID=${2}
IP=${3}
DEVICE=${4}
GATEWAY=${5}
FREQUENCY=""
OUTPUT=${6}

if [[ ${#} -eq 8 ]]; then # {
        FREQUENCY=${6}
        OUTPUT=${7}
fi
sed -e "s/\(empty-ssid\).*/${SSID}/g"      \
    -e "s/192\.168\.1\.20$/${IP}/g"        \
    -e "s/\(NanoBridge M.\)/${DEVICE}/g"   \
    -e "s/empty-frequency/${FREQUENCY}/g"  \
    -e "s/\(192\.168\.1\.1\).*/${GATEWAY}/g" ${FILE} > ${OUTPUT}
#END#

[Pacopag]

I just ran your script (excluding the sed line) and it seems to work.

Are you sure you're actually putting 8 arguments in the line? Your example only shows 7.

Also, I'm not sure you intend to separate the arguments with commas

[watael]

hi,

$ myFunc(){ one="$1" two="$2" three="$3" four="$4" five="$5" ; (($#==8)) && six="$6" seven="$7" || seven="$6"; echo "seven = $seven";}
$ myFunc 1 2 3 4 5 6 7 8
seven = 7
$ myFunc 1 2 3 4 5 6 7
seven = 6

[alf55]

How many different threads do you need for the same program???? This is at least the third one for this program.