Suppressing error messages in bash

[baysidelinux]

I have the following script to count how many files root and another user that I can access. Since I am not running it as root, find outputs errors for directories it cannot open. How can I supress these error messages so only the 2 lines I need will print.

#!/usr/bin/bash

root=`find / -user "root"|wc -l`
evlschemm=`find / -user "elschemm"|wc -l`

echo "I can access $root files owned by root"
echo "I can access $evlschemm files owned by elschemm"

[dtodd]

hi;

try running the script with:

$ ./myscript 2>/dev/null

the "2 > /dev/null" will pipe Standard Error (stderr) output to /dev/null (which means i'll not appear on the screen). Or try:

$ ./myscript 2>/tmp/myscript_errs.txt

to pipe any errors to a file (could be useful to check out for errors )

Enjoy!

[baysidelinux]

These dont seem to work, maybe they need to be logged in as root? I cant log in as root, well I will keep researching.
Thanks

[dtodd]

You're getting error messages from the output of the find command; try adding the "2>/dev/null" stderr suppression inside the script:

root=`find / -user "root" 2>/dev/null | wc -l `
evlschemm=`find / -user "elschemm" 2>/dev/null | wc -l`

[baysidelinux]

I was gonna try that to...Worked like a charm,
thanks

[dtodd]

Great; glad to help.

I forgot that stderr is written too on a "per-command-basis" ; so that's why you need to use the "2>/dev/null" after every command that could produce output you don't want to see.