help with `date '+%d-%B-%Y'`

[jsgehris]

Sould be very easy. If I have `date '+%d-%B-%Y'` in a shell script, and have:

echo `date '+%d-%B-%Y'`

It will show 21-April-2005

I would like it to show 21-04-2005, and need it also to read 21-4-2005, 21-04-05

Thanks for you help.

-Jeremy

[jeremy1701]

How about

%d-%m-%y

http://unixhelp.ed.ac.uk/CGI/man-cgi?date

BTW... Excellent name, dude.



Jeremy

[jsgehris]

BTW... Excellent name, dude.



Jeremy

Very Good. That made my day, post a message, and see the response from myself Just Kidding

Thanks for the url. But I see one thing wrong, I do it see anywhere to do like 4-21-2005 or 4-21-05, what about some where in the script to look for 01 -09 and take the 0 off?

-Jeremy

[jeremy1701]

But I see one thing wrong, I do it see anywhere to do like 4-21-2005 or 4-21-05, what about some where in the script to look for 01 -09 and take the 0 off?

I guess I don't understand what you're asking for here. If you want a double-digit year rather then a four digit year, use %y rather then %Y. If you need to read a date and convert it from one form to another, you're going to have to write a little code. If you need help doing that, post what you've got and we can see where you're at.

Jeremy

[jsgehris]

Ok, I see the year to make it 2, sorry. All I am doing is makeing dirs a cron job, and copying reports at work. They are picky about folder dates, and always say I want this and that for folder dates, and say if you can do it one way, you can do it another. The only other day format I do not see is exp 4-21-05 drop the 04. I have no clue how to do this. Makeing dirs it one thing. I know they sould not complane about the 0 but they do.

-Jeremy

[jeremy1701]

I don't see it either. I think you'll have to script that one. Shouldn't be too difficult.

Jeremy

[sarumont]

You could probably use sed to take the 0 off the beginning. I know no sed, but I'm fairly certain that's possible in it.

OTOH, it's quite possible in perl regexps.