Offset and Segment of an Address

[Alboin]

How does one go about finding the segment and offset of a 16-bit address? (For x86 -- real mode)

[CodeRoot]

I believe your question is very highly contextually dependent...

There is not a single answer - because there is not a one-to-one association of physical and segment : offset addresses. The 'x86' architecture actually requires that physical addresses be addressable by multiple segment : offset addresses (by design, 'relative' rather than 'fixed' addressing).

However, I would like to suggest that - for a 16-bit address, the segment would be zero - because [based on 'x86' architecture], the offset alone is a 16-bit number...

Hope this helps (at least a little)...

[Alboin]

Thanks...

Okay, so when I do something like this:

LDS, ds, [something-16bit]

What does LDS load in ds?

Edit: Fixed

[CodeRoot]

I do not believe 'LDS ds,----' is a valid instruction...