processing file..please help!!

[rashid2000]

my file has the following content:
name email
=== ====
jim jim@hotmail.com
susan susan@hotmail.com
....
name email
=== ====
ethan ethan@hotmail.com
stephen stephen@hotmail.com
...

the output should be:

jim jim@hotmail.com
susan susan@hotmail.com
....
ethan ethan@hotmail.com
stephen stephen@hotmail.com

any idea??

thanks

[neomax]

Hi,
If u already know what you wanna skip in ur parsing, I don't see what the problem is. U cud:
1] write a simple routing to read words (read one character at a time till u encouter a white space).
2] Check if the word is in the Avoid list.
3] if not forward it to output (whether ur writing it to another file or displaying it on screen).


Also, if ur allowed to change the format of input, you can have some sort of indicator at the start of lines that you wanna avoid, like if your file can look something like

#name email
#==== ====
jim jim@hotmail.com
susan susan@hotmail.com

then it becomes even easier... whenever u encouter a '#' just ignore till '\n'.

I know I'm asking you to hardcode a lot of things... so if someone has a more generic soln, I'm eagerly waiting for it.

[ghostdog74]

you just want to get all the lines with email addresses right?
eg
grep "@" file

[rashid2000]

..the lines after:

name email
=== ====

and the above lines occur n time (

[cyberinstru]

you just want to get all the lines with email addresses right?
eg
grep "@" file

As ghostdog74 suggested u can do that or try this script out:

#!/bin/bash

STR1="name email"
STR2="==== ====="
FILE="./addr.txt"
FD=6

exec $FD<$FILE

while read -u $FD LINE
do
if [ "$LINE" != "$STR1" ]
then
if [ "$LINE" != "$STR2" ]
then
echo $LINE;
fi
fi
done

exec $FD<&-

You can simplify multiple IF conditions thr...

[rashid2000]

cyberinstru,

I get the following error on running your script:

./s.sh: line 8: exec: 6: not found

#!/bin/bash

STR1="name email"
STR2="==== ====="
FILE="./addr.txt"
FD=6 # could u please explain me this line?????

exec $FD<$FILE # at this line!!!!!!!!!!!!

while read -u $FD LINE
do
if [ "$LINE" != "$STR1" ]
then
if [ "$LINE" != "$STR2" ]
then
echo $LINE;
fi
fi
done

exec $FD<&-

[cyberinstru]

FD=6 # could u please explain me this line?????

FD ... any file descriptor other than 0,1 and 2

exec $FD<$FILE # at this line!!!!!!!!!!!!

This line shud open the file $FILE (addr.txt - whr the email IDs and names are stored).

You can try this one by doing

exec 6<(filename)

at the command prompt, then execute the script. It shud work.

[rashid2000]

.. I get the error:
./s.sh: line 8: exec: 6: not found
((

[ghostdog74]

awk ' $0 !~ /name email/ && $0 !~ /=== ====/ { print }' file

[rashid2000]

ghostdog74,

I notice that the records ends with ^F (dec 06) , then new line.

The question is how to tell awk to skip if $0 matches that character ^F??

Thanks