rsh multicommand issue

[Sangal-Arun]

Can someone please tell me, why I'm getting an error mesg while trying to run the rsh command using a variable "a" and not getting an error mesg, when firing the same command (stored inside variable "a" on $ prompt)..................??? Do i need to export any variables or do a "cd" inside..!!!!

[/Fare/loggers/build] $ echo $c1; echo $c2; echo `hostname`
hostname -s
hostname -i
e1d1nas10.somecompany.com

[Fare/loggers/build] $ a="rsh -l build 53.3.101.185 \"$c1 ;$c2\""

[/Fare/loggers/build] $ echo $a
rsh -l build 53.3.101.185 "hostname -s ;hostname -i"

[/Fare/loggers/build] $ $a
bash: hostname -s ;hostname -i: command not found

[/Fare/loggers/build] $ `$a`
bash: hostname -s ;hostname -i: command not found

[/Fare/loggers/build] $ rsh -l build 53.3.101.185 "$c1 ;$c2"
e1d1nas10
53.3.101.185

[scm]

It's because the double quotes aren't being seen by your shell so the quoted string is appearing to rsh as a single command with embedded spaces. Try executing the variable with eval and see the difference! - $ eval $a