umask 666 vs 777 weird behaviour in Fedora Core 10

[diabloz]

Hello there

I am running Fedora core 10,non comercial under a VMachine

As I know any new created file has pernissions set to 666 - umask and a folder 777 - umask


But take a look at these :
I had to see for myself if it was true and i have created files named umask0xxx; the xxx standing for the umask set at each moment and then I "ls -l >>umask_all"
See that for umask0111, 123, 224 it looks like chmod is 777 - xxx not 666 -xxx
Only the last file umask0666 had chmod resulted from 666 - 666 why ???????
And in adittion I am able to " vi umask_all" and to " ls -l >> umaks_all" even if the file "umask_all" has "- --- --- ---" = 000

I am logged as gigi: x:0:0 , equal to root but not su, nor root

here are my calculations for what should result from 666 - xxx and 777 - xxx

666 - 224 = 442 = rw- rw- -w-
777 - 224 = 553 = r-- r-- -w-
666 - 022 = 644 = rw- r-- r--
777 - 022 = 755 = rw- r-- r--
666 - 666 = 000 = --- --- ---
777 - 666 = 111 = r-- r-- r--
666 - 123 = 543 = r-- r-- -w-
777 - 123 = 654 = rw- r-- r--
666 - 111 = 555 = r-- r-- r--
777 - 111 = 666 = rw- rw- rw-
666 - 000 = 666 = rw- rw- rw
777 - 000 = 777 = rw- rw- rw-



ls -l umask0* >>umask_all

total 24
-rw-rw-rw- 1 root root   7 2009-02-25 13:19 umask0000  OK (666 and 777)
-rw-rw-rw- 1 root root   9 2009-02-25 13:21 umask0111  777 wins
-rw-r--r-- 1 root root   7 2009-02-25 13:22 umask0123  777 wins
-r--r---w- 1 root root 120 2009-02-25 13:31 umask0224  777 wins
---------- 1 root root   9 2009-02-25 13:41 umask0666  666 wins 
---------- 1 root root 980 2009-02-25 13:54 umask_all

I can read umask_all with vi even if it has --- --- --- or 000

[signmem]

in linux , every file create can not get execute permission by default.

[diabloz]

in linux , every file create can not get execute permission by default.

ya right, jezz u think I do not know that

can't u see that I removed the "x" even if it resulted in there ??

why are u telling me that , it does not answer my question