String Variable count issue in Subscript

[deswoodau]

When executing the following shell script in (#!/bin/sh) I need to pass in 3 variables. Variable $2("C2P Services") is being read in by the subscript as two separate variables therefore my variable count check fails thinking I've passed 4 vars instead of 3. When I execute with var 2 being only a single word it works fine but I need to pass the entire string including the space as show below.

$ ./test-script.sh update "C2P Services" y

Script content

run_login_test ../bin/testServices.sh $1 "$2" $3

Subscript being called where failure occurs in (../bin/testServices.sh)

echo params echo here -$1- -"$2"- -$3- -$4-
echo num of param $#
if [ $# -eq 2 -a "$1" = "list" ]
then
serviceName="$2"
exec "$dir/cbib-was-client.sh" service-availability -service "$serviceName"
elif [ $# -eq 3 -a "$1" = "update" ]
then
echo here -$1- -"$2"- -$3-
serviceName="$2"
if [ "$3" = "y" -o "$3" = "Y" ]
then
available="true"
elif [ "$3" = "n" -o "$3" = "N" ]
then
available="false"
else
usage
fi
exec "$dir/cbib-was-client.sh" service-update-availability -service "$serviceName" -available "$available"
else
usage
fi


What can I do to enforce the subscript to ensure $2 is read in as full string rather than two separate values?

Thanks

[Rubberman]

Is the "run_login_test" a script as well (I assume it is)? Then "$2" will be two parts when it gets to testServices.sh. You need to further encapsulate it, as in

run_login_test ../bin/testServices.sh $1 "'$2'" $3

or

run_login_test ../bin/testServices.sh $1 "\"$2\"" $3