Help with "which" and environment variables please

[mgoblue0970]

Hello:

I have a new CentOS 6.3 installation. I'm a little confused about environment variables.

I installed the Java 7 SDK in /usr/java/jdk7

I placed a file called java.sh in /etc/profile.d... the contents of which are:

export JAVA_HOME=/usr/java/jdk7
export PATH=$JAVA_HOME/bin:$PATH

When I typed java -version from the command line, I got this:

OpenJDK Runtime Environment (IcedTea6 1.11.5) (rhel-1.50.1.11.5.el6_3-x86_64)
OpenJDK 64-Bit Server VM (build 20.0-b12, mixed mode)

Which is WRONG. So I did which java and got this:

/usr/bin/java

But if I do set | grep PATH

PATH=/usr/lib64/qt-3.3/bin:/usr/local/bin:/usr/bin:/bin:/usr/local/sbin:/usr/sbin:/sbin:/home/dogzilla/bin:/usr/java/jdk7/bin

I see the /usr/bin is in the path and I'm guessing that's how the OpenJDK gets seen instead of my install of the JDK.

The problem is, I obviously want "which java" to reflect my install and not the one in /usr/bin/java

Any assitance you can provide is greatly appreciated. Thanks!

[xa3apm]

Hello,

I am not an linux expert but you can check your system environment as use command env as there are few Java related veriables

JRE_HOME=/usr/java/default/jre
JAVA_BINDIR=/usr/java/default/bin
JAVA_HOME=/usr/java/default
SDK_HOME=/usr/java/default
JDK_HOME=/usr/java/default
JAVA_ROOT=/usr/java/default

try to change them to java you want to use.
I think it removing OpenJDK is a valid scenario.

I hope this helps.

Best Regards,
xa3apm