command to view list of ALL users and groups

[prosen]

---

Can nebody tell me a command ( or combo of cmds, so that I can put it in a shell script ) to view list of ALL users ( may or may NOT be logged in, preferably non-system users only ) ??
and something similar for a list of ALL groups ??

I need it badly but cant really figure it out ...

[serz]

cat /etc/passwd | cut -d: -f1
cat /etc/group |cut -d: -f1

[prosen]

ok .. that is fine ...
now a little bit more .. the output of cat /etc/passwd | cut -d: -f1
shows system users as well .. I want to show only the non-system users,
like my own user account, but NOT root, etc.
ie., on my system, general users have UIDs starting frm 500, so I just wanna check the 3rd field of each line in the passwd file and accordingly print them.

Please help someone, I know this can be done (probably using awk or sed), bcos I had seen similar things before, though I dont remember now.

Thanks for everything so far..

[Cabhan]

#!/usr/bin/perl -w

open PASSWD, "/etc/passwd" or die "$0: Cannot Open File /etc/passwd For Input!!\n";

while&#40;<PASSWD>&#41;
&#123;
    /^&#40;\w+&#41;&#58;x&#58;&#40;\d+&#41;/;

    if&#40;$2 > 500&#41;
    &#123;
        print "$1\n";
    &#125;
&#125;

Heh, I tried writing it in Bash first (and it almost worked!), but here it is in Perl, which I actually know .

[prosen]

Just figured out another one ...

#!/bin/sh

awk -F&#58; '&#123;if &#40;$3>=500 && $3<=1000&#41; print&#125;' /etc/passwd | cut -d&#58; -f1

The $3<=1000 is for the nfsnobody user a/c which has an UID of 65534.

Thanks anyway Cabhan, I have already copied your perl soln and added to my archives.

[Cabhan]

I think that just everyone hates me .

Hehe, everytime I write some sort of script, someone replies with like a two-line Bash command. Damn you all.

[prosen]

hmmm .. well actually its NOT that I do not like perl. I simply have never really had the enthusiasm and time to learn it well, as of now. however, I do know about the various capabilities of perl and unless I would have got that soln before checking your reply, I would have stuck to your version only.
But then, as I have said already, I do collect scripts which look interesting to me, and yours is definitely one of them.

[bigtomrodney]

Man I am really gonna have to get familiar with gawk. Every time I thinkg I get an idea someone else shows me it at work and I go 'cool'. Cheers for that code, will be used! Although a lot of my new users have much higher UIDs so I've modified it a bit.

[prosen]

an even shorter one, dunno y it did not come to my mind earlier :

#!/bin/sh

awk -F&#58; '&#123;if &#40;$3>=500 && $3<=1000&#41; print $1&#125;' /etc/passwd

[CodeRoot]

I think that just everyone hates me.

You are letting your imagination run wild...

Hehe, everytime I write some sort of script, someone replies with like a two-line Bash command.

How about this:

#!/usr/bin/perl -w
open PASSWD, "/etc/passwd" or die "$0: Cannot Open File /etc/passwd For Input!!\n";
while(<PASSWD>) { /^(\w+):x:(\d+)/; if($2 > 500) { print "$1\n"; } }

(It doesn't make yours less valid.)

Damn you all.

"Now, that's not nice..."