Find and replace command

[cheriyamoozhiyilcinu]

Hi Everybody,

I am having some issues with one of my shell script, I
will explaing the whole issue.

In my script I am declaring a variable as shown below

var=`cat
/home/DTEDIT/new_build/"$1"/inst/data/postgresql.conf
|grep "port =" | awk -F " " '{ print $3;}'`

Now what I am doing with this command is checking for
the postgresql.conf file for the existance of port =,
it gives me a value say for example 5999, now this
5999 is stored in var...

The major issue starts from here, this variable var I
want to subsititue into another file called
postgres.properties file at the location where it says
localhost:5678, I want to replace that 5678 by the
variable var, I want to change that from 5678 to 5999.
Please tell me if there is any find and replace command
that I can call through my shell script.
Please suggest any solution.


Thanks in advance

Regards
Cinu

[bknorr]

This is happening in another thread right now too:

sed 's/5678/5999/g'

or....?

sed 's/5678/$1/g'

Something like this? http://www.student.northpark.edu/pem...d/sed1line.txt .

[cheriyamoozhiyilcinu]

Thanks a lot,

I was able to get the solution with teh sed command