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I have tightvnc on the other machine-set up correctly I hope.
it has its 2 passwords
I have its LAN address and port number
192.168.1.2 and 5900
I've initialized Samba ...
- 09-29-2008 #1Linux Newbie
- Join Date
- Apr 2005
- Location
- West Oz
- Posts
- 140
configuring VNC in 10.3 for tightvnc (win)
I have tightvnc on the other machine-set up correctly I hope.
it has its 2 passwords
I have its LAN address and port number
192.168.1.2 and 5900
I've initialized Samba automatically.
I Left click krdc and also "Connect to a remote VNC desktop"
An addressbox appears, with a temporary form indicator which says
vncserver:1
(host
ort/screen)
What is "vncserver" pls?
What is "screen" pls?
The addressbox contains the start
"vnc:///" and automatically puts a "/" at the end of any input.
I've tried:
vnc:///192.168.1.2/5900:1/
and similar, but all my entries get a bland:-
"the form of the address is incorrect"
Pls, I am not a programmer, how do I make the connection work????2.6GHz Celeron, 1GB, 160GB, 128Mb SuSe11.2; PCTV, GBit eth0 on P4PE, 10/100 eth1 <Ride to ride again>.
- 09-29-2008 #2
Try address 192.168.1.2:5901
- 09-29-2008 #3Linux Newbie
- Join Date
- Apr 2005
- Location
- West Oz
- Posts
- 140
- 09-29-2008 #4
Assuming that the server was started on the other machine:
...and it tells you that the "1" instance of vnc is running...Code:vncserver
...you should be able to log into the server from the other machine (client) provided port 5901 isn't blocked and the LAN IP is correct. From the client machine's command line, it should be a matter of just doing:Code:bash-3.2$ vncserver New 'X' desktop is dapperdan:1 Starting applications specified in /home/dapperdan/.vnc/xstartup Log file is /home/dapperdan/.vnc/dapperdan:1.log
Code:vncviewer 192.168.1.2:5901


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