Using 'sed'

[anaigini45]

I have about 7 '*.cgi files' in /cgi directory and 1 insert.pl file in /bin . All these files have one line of code which is :

 use bin = /path/to/directory 
  

I would like to replace the use bin path to another path in all those files.

Is this line of code correct to do so :

find /cgi -name "*.cgi" -exec sed -i "%s,/old/path,/new/path,g" '{}' \;

How do I execute this command for both the *.cgi files in /cgi and insert.pl in /bin at one time?

[jaduks]

Something like this:

$ cat work/test1/a.cgi 
use bin = /path/to/directory 
Some other lines

$ cat work/test1/b.cgi 
use bin = /path/to/directory 
Some other lines

$ cat work/dir2/c.pl   
use bin = /path/to/directory 
This is a perl file

$ find work/test1/ work/dir2/ -type f \( -iname "*.cgi" -or -iname "*.pl" \)
work/test1/b.cgi
work/test1/a.cgi
work/dir2/c.pl

$ for fl in $(find work/test1/ work/dir2/ -type f \( -iname "*.cgi" -or -iname "*.pl" \)); do echo $fl; sed '/use bin/ s!/path/to/directory!/path/to/directory1!g' $fl > $fl.bak ; mv -v $fl.bak $fl ;   done

work/test1/b.cgi
`work/test1/b.cgi.bak' -> `work/test1/b.cgi'
work/test1/a.cgi
`work/test1/a.cgi.bak' -> `work/test1/a.cgi'
work/dir2/c.pl
`work/dir2/c.pl.bak' -> `work/dir2/c.pl'

$ cat work/test1/a.cgi 
use bin = /path/to/directory1 
Some other lines

$ cat work/test1/b.cgi 
use bin = /path/to/directory1 
Some other lines

$ cat work/dir2/c.pl   
use bin = /path/to/directory1 
This is a perl file

Regards,
Jadu

[chebarbudo]

What about this one?

(find /cgi -name "*.cgi"; find /bin -name "insert.pl") | while read -r; do
    sed -ri "s,^(use bin =) /old/path$,\1 /new/path,g" "$REPLY"
done